What is the y-intercept of the equation of the line that is perpendicular to the line y = 3/5x + 10 and passes through the point (15, –5)? the equation of the line in slope-intercept form is y =-5/3 x +

Y = 3/5x + 10...slope here is 3/5. A perpendicular line will have a negative reciprocal slope. All that means is flip the slope and change the sign. So we need a slope of -5/3

y = mx + b
slope(m) = -5/3
(15,-5)...x = 15 and y = -5
now we sub for b, the y int
-5 = -5/3(15) + b
-5 = -25 + b
-5 + 25 = b
20 = b

so ur perpendicular equation is : y = -5/3x + 20

The length of what is left would be 1 1/2 feet long.