Determine all the roots of f(t)=9t^3-18t^2+6t

Hello :
f(t) = 0 :    3t(3t²-6t+2) = 0
(t=0) or (3t²-6t+2 = 0 )
Δ = b²-4ac     a=3       b=-6      c=2
Δ = (-6)²-4(3)(2) =36-24 =12 =(2√3)²
x1 =( 6-2√3)/6        x2 =( 6+2√3)/6
the roots are : 0 , ( 6-2√3)/6 , ( 6+2√3)/6

When rates are expressed as a quantity of 1, such as 2 feet per second or 5 miles per hour, they are called unit rates. if you have a multiple-unit rate such as 120 students for every 3 buses, and want to find the single-unit rate, write a ratio equal to the multiple-unit rate with 1 as the second term.