Atrapezoid has an area of 5 1/2 ft sq. if the trapezoid has a base that measures 2 3/5 ft and a height of 1 1/2 ft, what is the length of the other base?

First of all, let us change all the mixed number into improper fraction:
5 1/2=11/2
2 3/5=13/5
1 1/2=3/2
Area of the trapezoid=
1/2(b1+b2)×h

11/2=1/2(13/5+b2)×3/2
Divided 3/2 or multiply 2/3 for both side
11/2×2/3=1/2(13/5+b2)×3/2×2/3
11/3=1/2(13/5+b2)
Multiply 2 for both side
11/3×2=1/2(13/5+b2)×2
22/3=13/5+b2
Subtract 13/5 for both side
b2= 4 11/15. As a result, the length of other base is 4 11/15 feet. Hope it help!