What is the area of the shaded region?
(25π – 48) cm2
(25π – 30) cm2
(25π – 24) cm2
(25π – 12) cm2

We are given a circle with a partially shaded region. First, we need to determine the area of the whole circle. To do this, we need the measurement of the radius of the circle:

Use the Pythagorean theorem to solve for the other leg of the right triangle inside the circle:

5^2 = 3^2 + x^2
x = 4

The radius is 4 + 1 cm = 5 cm

So the area of the circle is A = pi*r^2
A = 3.14 * (5)^2 
A = 25pi cm^2

To solve for the area of the shaded region:

Ashaded = Acircle - Atriangles

we need to solve for the area of the triangles:

A = 1/2 *b*h
A = 1/2 *6 * 5
A = 15 cm^2

Atriangles = 2 * 15 
Atriangles = 30 cm^2

Ashaded = 25pi - 30

7.666270253x10 raised to the 18th power