Triangle mnp is dilated according to the rule do,1.5 (x, y)(1.5x, 1.5y) to create the image triangle m'n'p, which is not shown.

what are the coordinates of the endpoints of segment m'n'?
m'(-6, 9) and n'(4, 9)
m'(-6, 9) and n'(3, 9)
m'(-2, 3) and n'(7, 9)
m'(-2, 3) and n'(1, 3)

Option B is correct i.e.,  M'(-6,9) and N'(3,9).

Step-by-step explanation:

Given: ΔMNP mapped in graph ⇒ coordinates of vertices are M(-4,6), N(2,6) & P(-1,1)  and scale factor of dilation is 1.5 .i.e., 1.5(x,y) ⇒ (1.5x,1.5y)

ΔMNP dilated to ΔM'N'P'

To Find: Coordinates of M' &N'

since, scale factor of dilation is 1.5.

we get coordinates of M' by multiplying coordinates of M

⇒1.5 M(-4,6) = M'(1.5×(-4), 1.5×6)

                    =M' (-6,9)

similalrly coordinates of N' by multiplying coordinates of N

⇒1.5 N(2,6) = N'(1.5×2, 1.5×6)

                    =N' (3,9)

The coordinates of the endpoints of segment M'N' is M'(-6,9) and N'(3,9)

∴Option B is correct.

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

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