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ron buys a lawnmower for $1,500. the salesperson says the value will depreciate about 30% per year over the next few years. however, his neighbor says it is likely to depreciate about $300 per year.

which system could be used to determine when the two depreciation models will give the same value for the lawnmower?

y = 1,500(0.3)^x and y = 1,500 - 300x
y = 1,500(0.7)^x and y = 300 - 1,500x
y = 1,500(0.7)^x and y = 1,500 - 300x
y = 1,500(0.3)^x and y = x - 300

Step-by-step explanation:

Given : Ron buys a lawnmower for $1,500. The salesperson says the value will depreciate about 30% per year (r=0.3) over the next few years.

The exponential decay equation is given by :-

, where A is the initial amount , r is rate of decay and x is the time period.

Then , the equation of depreciation for Ron :-

However, his neighbor says it is likely to depreciate about $300 per year, which is linear depreciation.

The linear equation is given by :-

, where 'c' is the initial amount and 'a' is the  rate of change.

Then equation of depreciation for his neighbor :-

Thus , the system could be used to determine when the two depreciation models will give the same value for the lawnmower:-

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.

6(h+1)/2=a

a=area

step-by-step explanation:

its the same thing as a square or rectangle but after multiplying two sides you need to divide it by two.