What is the greatest common factor of 110, 40, and 120?

10

Step-by-step explanation:

To find : The greatest common factor of 110, 40, and 120

We first write the prime factorization of 110, 40, and 120 as follows:

From the above prime factorization, we can see that the greatest common factor of 110, 40, and 120 =

Hence, the greatest common factor of 110, 40, and 120 =10

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

step-by-step explanation: