Arectangular wall has a length of 12 ft and a width of 8 ft. the wall has two rectangular windows. each window has a width of 3 ft and a height of 5 ft. andrea chooses a point on the wall at random to test a new paint color. what is the probability she could choose a point on a window?
enter your answer, as a decimal rounded to the nearest hundredth, in the box.

The  probability she could choose a point on a window is:

0.31 or 31.25%

Step-by-step explanation:

It is given that the length of wall=12 ft.

Width of wall=8 ft.

Area of wall=Length of wall×Width of wall

Area of wall=12×8

Area of wall=96 square ft.

Similarly we are given length of window=3 ft.

Width of window=5 ft.

Hence, Area of 1 window=3×5=15 square ft.

As there are two windows.

Hence, total area of windows=2×15=30 square ft.

Hence, the probability of choosing a point on a window is ratio of the area of window to the total area of the wall.

Hence, Probability=30/96=0.3125

which could also be represented as:

31.25%

Hence,Probability=0.31 or 31.25%

c) the median for town a 30" is greater than the median for town b 25"

step-by-step explanation:

town a, median = q2 = 30

town b, median - q2 = 25

so the median for town a 30" is greater than the median for town b 25"