![\bf \displaystyle \int\limits_{1}^{9}\ \sqrt{x}\cdot dx \iff\displaystyle \int\limits_{1}^{9}\ x^{\frac{1}{2}}\cdot dx \\\\\\ \cfrac{x^{\frac{1}{2}+1}}{\frac{1}{2}+1}\implies \cfrac{x^{\frac{3}{2}}}{\frac{3}{2}}\implies \left. \cfrac{2\sqrt{x^3}}{3} \right]_{1}^{9}](/tpl/images/0429/8246/a7c2d.png)
9
∫√x dx
1
Mathematics, 22.12.2019 14:31 famouzgal
On the integral of 1 to 9, what is sqrtx in respect to x?
9
∫√x dx
1
(sorry not sure how else to write
Answers: 2
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On the integral of 1 to 9, what is sqrtx in respect to x?
9
∫√x dx
1
9
∫√x dx
1
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