Mathematics, 30.01.2020 04:58 tzartiger12

Prism a is similar to prism b. the volume of prism a is 2720 cm³.

what is the volume of prism b?

a.21,760 cm³

b.1360 cm³

c.680 cm³

c.340 cm³

Prism a is similar to prism b. the volume of prism a is 2720 cm³. what is th

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Answer from: 29delphina

ANSWER

340 cm³

EXPLANATION

From the diagram we can determine the scale factor for the sides of the prisms.

Taking prism A to be the object and prism B to be the image,

The scale factor is

$k = \frac{4}{8} = \frac{1}{2}$

The scale factor for the volume is

${k}^{3} = \frac{1}{8}$

Since the volume of prism A is 2720cm³, we multiply this by the scale factor of the volume to get the volume of prism B.

Volume of prism B is

$= \frac{1}{8} \times 2720c {m}^{3}$

$= 340c {m}^{3}$

Answer from: lucretiak74

Volume for Prism B = 340 cm³

Given

Prism A is similar to Prism B.

From figure

Length of one side of Prism A = 8 cm

Length of one side of Prism B = 4 cm

The volume of Prism A is 2720 cm³.

The scale factor is defined as given below

Let the scale factor be represented as S

$\rm S = Scale \; factor = \dfrac{Final \; Length }{Initial \; Length } \\S = Scale \; factor = \dfrac{4 }{8 } = \dfrac{1}{2} \\$

The scale factor for volume of the given prism can be given as $\rm \bold{S^3}$

So the scale factor for given prism

$\rm Scale \; factor\; for \; the \; given \; prism = (1/2)^3 = \dfrac{1}{8}$

Volume of Prism A = 2720 $\rm {cm}^3$

So the Volume for Prism B can be calculated as

$\rm(Volume \; of\; Prism \; A ) \times \bold S = \dfrac{2720 }{8} = 340 \; {cm} ^3$

Volume for Prism B = 340 cm³

For more information please refer to the link below

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Answer from: Quest

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf =

pf = 6,25 u

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step-by-step explanation:

Answer from: Quest

step-by-step explanation:

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