Find the cube roots of 27(cos 327° + i sin 327° ). Write the answer in trigonometric form.

3(cos 109° + i sin 109°)

3(cos 229° + i sin 229°)

3(cos 349° + i sin 349°)

Step-by-step explanation:

27(cos 327° + i sin 327°)

Modulus: 27^⅓ = 3

Arguments:

327/3 = 109

(327+360)/3 = 229

(327+2(360))/3 = 347

Cube roots are:

3(cos 109° + i sin 109°)

3(cos 229° + i sin 229°)

3(cos 349° + i sin 349°)

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation:

answer: can you give the

step-by-step explanation: