Conner and jana are multiplying (3^5 6^8)(3^9 6^10).
conner's work
(3^5 6^8)(3^9 6^10) =...
Mathematics, 24.12.2019 19:31 colton1788
Conner and jana are multiplying (3^5 6^8)(3^9 6^10).
conner's work
(3^5 6^8)(3^9 6^10) = 3^5+^9 6^8+^10 = 3^14 6^18
jana's work
(3^5 6^8)(3^9 6^10) = 3^5β
9 6^8β
10 = 3^45 6^80
is either of them correct? explain your reasoning.
(i dont rly get this question)
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