The end point in a titration of a 43ml sample of aqueous lactic acid was reached by addition of 16mlof0.22MKOH titrant. One mole of acid was titrated by one mole of base. What is the molar concentration of lactic acid

0.082 M

Explanation:

First we calculate the moles of KOH added, by multiplying its volume and concentration:

Given that one mole of acid reacts with one mole of base, in the lactic acid sample there were 3.52 acid moles as well.

Finally we divide the acid moles by the volume, to calculate the concentration:

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the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3