How to solve this? \[\int xe^{6x}dx \]

Let u = x 
dv = e^(6x) dx 
v = e^(6x)/6 
du = dx 
uv - ∫v du 
x*e^(6x)/6 - ∫e^(6x)/6 dx eval. from 0 to 1 
x*e^(6x)/6 - e^(6x)/36 eval. from 0 to 1 
= e^(6)/6 - e^(6)/36 + 1/36 
= (5*e^6 + 1)/36

The first one, i believe, would be correct. all the others have one thing in common, and that's that they have repeating numbers. in the second one, x and y have repeating 6's and 3's, and in the third, x and y have repeating 6's as well. in the last one, there are repeating 3's. the first one has no repeating numbers.

Idon’t know what the answer is i wish i could