X2 – 6x + 8 = 0 is x = 2. What is the other solution?

x₁ = 4

x₂ = 2

Step-by-step explanation:

x² - 6x + 8 = 0

x² - 2x - 4x + 8 = 0

x(x - 2) - 4(x - 2) = 0

(x - 4)(x - 2) = 0

x - 4 = 0 => x₁ = 4

x - 2 = 0 => x₂ = 2

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b