Gerald has a bag of 10 colored balls: 3 green, 3 red, and the rest yellow. He randomly draws two balls, one at a time without replacement. Find the probability of drawing at least one yellow ball.

2/3

Step-by-step explanation:

Probability is the ratio of the number of possible outcome to the number of total outcome.

Given that there are 10 balls of which 3 green, 3 red, and the rest yellow

Number of yellow balls = 10 - 3 - 3 = 4

Probability of picking a;

Green ball  = 3/10

Red ball = 3/10

Yellow ball = 4/10

If two balls are picked without replacement, the probability that one is at least yellow will be

YR RY YG GY YY

= 4/10*3/9 + 3/10*4/9 + 4/10*3/9 + 3/10*4/9 + 4/10*3/9

=12/90 *5

= 2/3

apex answer is: true.