To investigate the relationship between age and preference for two mayoral candidates in an upcoming election, a random sample of city residents was surveyed. The residents were asked which candidate they preferred, and each resident was classified into one of three age-groups. The test statistic for the appropriate hypothesis test was 3.7408. Approximately what is the probability that the observed responses would be as far or farther from the expected responses if there is no association between age-group and preference? A. 0.0001
B. 0.1541
C. 0.2908
D. 0.5873
E. 0.7117

A. 0.0001

Step-by-step explanation:

z-statistic:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

The value of the z-statistic is z = 3.74.

The desired probability is 1 subtracted by the pvalue of z = 3.74.

z = 3.74 has a pvalue of 0.9999

Then

1 - 0.9999 = 0.0001.

So the correct answer is given by option A.

B. .1541

Step-by-step explanation:

Not sure why but the teacher answer key had this listed, came on here to see why

answer: the correct one is a

step-by-step explanation:

f is the midpoint of