A furniture store pays a wholesale price for a mattress. Then, the store marks up the retail price to 150% of the
wholesale price. Later, they put the mattress on sale for
50% off of the retail price. A customer just bought the
mattress on sale and paid $1,200.
a. What was the retail price of the mattress, before the
discount?

Step-by-step explanation:

Part A:

Given that the mattress is sold for 50% off of the retail price, let the retail price of the mattress be x, then

50% of x = 1200

⇒ 0.5x = 1200

⇒ x = 1200 / 0.5 = 2400

Therefore, the retail price of the mattress, before the discount is $2,400.

Part B:

Given that the store marks up the retail price to 150% of the wholesale price. Let the whole sale price be p, then

(100% + 150%) of p = 2400

250% of p = 2400

2.5p = 2400

p = 2400 / 2.5 = 960.

Therefore, the wholesale price, before the markup was $960

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.