Suppose a bus arrives at a bus stop every 40 minutes. if you arrive at the bus stop at a random time, what is the probability that you will have to wait at least 10 minutes for the bus? write the probability as a simplified fraction.
pl hahaha

=3/4

Step-by-step explanation:

A bus arrives at a bus stop every 40 minutes.

You arrive at a bus stop at a random time.

So, probability that you will wait at most 10 minutes = 10/40

So, The probability that you will wait at least 10 minutes= 1-10/40

=1- 10/40

By taking L.C.M we get;

=40-10/40

=30/40

=3/4

Thus the probability that you will have to wait at least 20 minutes for the bus is 3/4

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,