A cone fits inside a square pyramid as shown. For every cross section, the ratio of the area of the circle to
Since the area of the circle is the area of the
square, the volume of the cone equals
the area of the square is
or 7
402
o the volume of the pyramid or - Alenchor
arh.
Cross section
r
o the volume of the pyramid or
+(1200)
2n.
o the volume of the pyramid or z { nºm) or
7
2r
2r
22h.
0 Į the volume of the pyramid or = { 29°m) oraz
arh.
m no

Answer on Question #47534 – Math – Geometry

How to prove the volume formula of con is 1/3×π×r^2×h;without using

integration?

Solution.

Suppose we take a slice of the pyramid with the cone inside, from some way up

the pyramid. This will look like a square with a circle fitting inside. Radius of the

cone at this point, will be x.

The area of the circle is

The area of the square is × =

The ratio of the circle to the square is

.

The same is true for every slice we take: the area of the circle is

of the area

of the square.

So, the volume of the cone will be

the volume of the pyramid.

The pyramid's volume is

.

So the cone's volume is

∗

=

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph