PLEASE HELP! The AHS football team did a weigh-in at the start of training camp and the weights of the players were distributed normally. There were 60 players at the start of camp. How many players are within one standard deviation of the mean?

This is very simple. All you have to do is multiply 60, the number of players, with 68% the proportion of players that are within one standard deviation from the mean.
Therefore:
60*0.68= 40.8
You should go with 40 players in this case to be conservative but if ur teacher says otherwise go with 41

The answer would be 5< 6n