En una granja se crían gallinas y cerdos. Entre las dos clases de animales hay 40 cabezas y 110 patas. ¿Cuántos animales hay de cada clase?

Total pigs in the farm = 15

Total chickens in the farm = 25

Step-by-step explanation:

Given - Chickens and pigs are raised on a farm. Between the two classes

             of animals there are 40 heads and 110 legs.

To find - How many animals are there of each class?

Proof -

Given that , there are two types of animals - Chicken and pigs.

Let Chicken is represented by c

      Pigs are represented by p

Given , there are 40 heads and 110 legs.

As we know that both chicken and pigs has 1 head

⇒1c + 1p = 40

⇒c + p = 40                 (1)

Also, we know

Chicken has 2 legs whereas pigs have 4 legs

⇒2c + 4p = 110

Divide the whole equation by 2, we get

⇒c + 2p = 55                 (2)

∴ we get

c + p = 40                 (1)

c + 2p = 55                 (2)

subtract equation (1) from equation (2) , we get

c + 2p - ( c+ p) = 55 - 40

⇒c + 2p - c - p = 15

⇒p = 15

Now,

Put the value of p in equation (1), we get

c + 15 = 40

⇒c = 40 - 15

⇒c = 25

∴ we get

c = 25

p = 15

So, Total pigs in the farm = 15

Total chickens in the farm = 25

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step-by-step explanation:

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.