What is the mass of 8.83 × 10 ^23 formula units of iron (III) oxide, Fe2O3?

234.68g

Explanation:

We understood from Avogadro's hypothesis that 1mole of any substance contains 6.02x10^23 atoms. Therefore, 1mole of Fe2O3 also contains 6.02x10^23 atoms

1 mole of Fe2O3 = (56x2) + (16x3) = 112 + 48 = 160g

Now, if 160g of Fe2O3 contains 6.02x10^23 atoms,

Therefore Xg of Fe2O3 will contain 8.83×10^23 atoms i.e

Xg of Fe2O3 = (160x8.83×10^23)/6.02x10^23 = 234.68g

if you mean hydrogen and oxygen then water is the product