Help plz 20 points do all work

1.7x+1y

2.9x+8n

3.-1r-4n+9y

4.17y-9x

5.-9n-r

Step-by-step explanation:

Combine Like Terms!

Hope this helps! :)

1. 8x + 3y - x - 2y

= 8x - x + 3y - 2y

= 7x + y

2. 3n - 7n - 2n + x + 8x

= 3n - 9n + 9x

= - 6n + 9x

3. 2r - 5n + 9y - 3r + n

= 2r - 3r - 5n + n + 9y

= -r - 4n + 9y

4. 12y - 6x + 5y - 3n

= 12y + 5y - 6x - 3n

= 17y - 9n

5. - 13n + 4n - r

= -9n - r

6. 7xy - 8x + 6xy - y

= 7xy + 6xy - 8x - y

= 13xy - 8x - y

7. - 14r - 10n - 3r - 9n

= -14r - 3r - 10n - 9n

= - 17r - 19n

8. 6r + 9r - 2r - 13n

= 6r + 7r - 13n

= 13r - 13n

9. n + r + x - 3x +4r

= n + r + 4r + x - 3x

= n + 5r - 2x

10. 15y - 7x + 9z + 4z - 3x

= 15y - 7x - 3x + 9z + 4z

= 15y - 10x + 13z

Step-by-step explanation:

You just have to group like terms and then 'add' or 'subtract'.

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!