Help!! 5.1 q2 Algebra

4y^2-y+21

Step-by-step explanation:

(4y-5y)+(5y^2-y^2)+(-6+27)

-y+4y^2+21

put it in standard form

4y^2-y+21

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x