74% of 19 year old males are atleast 172 pounds , what percent of the males are not atleast 172 pounds?

The percentage of males are not at least 172 pounds

P(X⁻ ≥ 172) = 0.26

Step-by-step explanation:

Step(i):-

Given that 74% of 19 -year -old males are at least 172 pounds

Let 'X' be a random variable in a binomial distribution

P( X≥172) = 74% = 0.74

we have to find that the percentage of males are not at least 172 pounds

Step(ii):-

The probability of males are not at least 172 pounds

P(X⁻≥172) = 1- P( X≥172)

                 = 1- 0.74

                 = 0.26

Final -

The percentage of males are not at least 172 pounds

P(X⁻ ≥ 172) = 0.26

don't know sorry bru

step-by-step explanation: