(x+yi)-(-6+14i) = 18+2i

Can somebody help me solve for X and Y

Equation A: x = -1 and y = 3
Equation B: x = 12 and y = 16
Step-by-step explanation:
In the complex numbers (a + bi) and (x + yi)
(a + bi) + (x + yi) = (a + x) + (b + y)i
(a + bi) - (x + yi) = (a - x) + (b - y)i
Equation A
∵ (x + yi) + (4 – 7i) = 3 – 4i
∴ (x + 4) + (y - 7)i = 3 - 4i
→ Compare the real parts and compare the imaginary parts
∴ x + 4 = 3 and y - 7 = -4
∵ x + 4 = 3
→ Subtract 4 from both sides
∴ x + 4 - 4 = 3 - 4
∴ x = -1
∵ y - 7 = -4
→ Add 7 to both sides
∴ y - 7 + 7 = -4 + 7
∴ y = 3
Equation B
∵ (x + yi) - (-6 + 14i) = 18 + 2i
∴ (x - -6) + (y - 14)i = 18 + 2i
→ (-)(-) = (+)
∴ (x + 6) + (y - 14)i = 18 + 2i
→ Compare the real parts and compare the imaginary parts
∴ x + 6 = 18 and y - 14 = 2
∵ x + 6 = 18
→ Subtract 6 from both sides
∴ x + 6 - 6 = 18 - 6
∴ x = 12
∵ y - 14 = 2
→ Add 14 to both sides
∴ y - 14 + 14 = 2 + 14
∴ y = 16

X=12-yi+16i
Y= -12i+xi +16
I hope this helps

10.4 is the answer for you

Ithink your answer is c hope that