Nesesito ayuda con este problema ​

Hi sorry i don’t speak spanish :(

x=5
y=52

since AB and BC are the same length, you know it is an isosceles triangle
so two of the angles are the same
angle A and angle C are the same
so y = 52
A = C :. y = 52

all angles of a triangle add to 180
so add 52 and 52 to get 104
subtract 104 from 180 to get 76
set 14x + 6 = 76
14x = 70
x = 5

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12

12 rio aoice of q kqpd so r lagr