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Mathematics, 16.02.2021 17:10 S28462182

Please solve these for me I'm due on Thursday:( 9) 2x 2βˆ’ 3x βˆ’ 15 = 5
10) x 2+ 2x βˆ’ 1 = 2
11) 2k 2+ 9k = βˆ’7
12) 5r 2= 80
13) 2x 2βˆ’ 36 = x
14) 5x 2+ 9x = βˆ’4
15) k 2βˆ’ 31 βˆ’ 2k = βˆ’6 βˆ’ 3k 2βˆ’ 2k
16) 9n 2= 4 + 7n
17) 8n 2+ 4n βˆ’ 16 = βˆ’n 2
18) 8n 2+ 7n βˆ’ 15 = βˆ’7

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Please solve these for me I'm due on Thursday:( 9) 2x 2βˆ’ 3x βˆ’ 15 = 5
10) x 2+ 2x βˆ’ 1 = 2
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