Assume that women's heights are normally distributed with a mean of 45.7 inches and a standard deviation of 2.25 inches. If 900 women are randomly selected, find the probability that they have a mean height between 45 inches and 45.6 inches.

where are the images of the functions i can only see the question you typed.

step-by-step explanation:

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²

one fourth of 9% = 2.25%

gavin is correct in saying : the equivalent quarterly interest rate would be

2.25%.

yes, whats the problem?