What is the distance between the points (-2, 1) and(1,3) ?Round your answer to the nearest tenth

To answer this question we're going to need to use the distance formula, which is

d = √((x2 - x1)2 + (y2 - y1)2)

We are given two points:

(x1, y1) = (-2, 1)

(x2, y2) = (-5, 3)

d = √((-5 - (-2))2 + (3 - 1)2)

= √((-3)2 + (2)2)

= √(9 + 4)

= √(13)

≈3.6056

Since it says to round to the nearest tenth, the distance between the 2 points is

3.6 units

d=3.6

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

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