Ayasha and Michael draw cubes. Each side of Ayasha cube has a length of 7 m each side of Michael's cube has a link that is double the length of Ayasha cube compare the surface areas of the cubes

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  Michael's cube has 4 times the surface area of Ayasha's cube

Step-by-step explanation:

When linear dimensions of similar figures are scaled by a factor k, their surface areas are scaled by the factor k², and their volumes are scaled by the factor k³.

Here, Michael's cube is 2 times the length of Ayasha's cube, so the surface area of his cube will be 2² = 4 times the surface area of Ayasha's cube.

The surface area of the cube is ...

  A = 6s²

so Ayasha's cube has an area of ...

  A = 6(7 m)² = 294 m²

Michael's cube has an area of ...

  A = 6(2·7 m)² = 4·294 m² = 1176 m²

3030 ur welcome

step-by-step explanation:

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.