A particle P is moving with constant velocity (–3i + 2j)ms-1. At time t = 6s P is at the point with position vector (–4i – 7j)m.

Find the distance of P from the origin at time t = 2 s.

I know the answer is 17m but can someone explain how they get there, much appreciated.

triangle abc is reflected on the line x=-6.5 then reflected again on the x axis

step-by-step explanation:

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step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)

graph them on a graphing calculator, press 2nd trace. select intersect. hit enter until it says answer. ti 84 works best

step-by-step explanation: