Miles has a train collection with 36 engines, 72 boxcars, and 18 cabooses. He wants to arrange the train cars in equal rows with only one type of train car in each row. How many can he put in each row? Mark 4 that apply.

Kindly check explanation

Step-by-step explanation:

Given that:

Number of engines = 36

Number of car boxes = 72

Number of cabooses = 18

To areange in equal rows :

We need to obtain the greatest common factor :

Factors of :

36 : 2, 3, 4, 6, 9, 12, 18, 36

18 : 2, 3, 6, 9, 18

72 : 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

The greatest common factor (GCF) is 18

Number that can be put in each row :

Cabooses :

18 / GCF = 18 / 18 1 row

Engines :

36 / GCF = 36 /18 = 2 rows

Box cars :

72 / GCF = 72 / 18 = 4 rows

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x