Write the equation of the line that passes through the points (-8,3)(−8,3) and (3,2)(3,2). Put your answer in fully reduced point-slope form, unless it is a vertical or horizontal line.

y-2= - 1/11 (x-3)

Step-by-step explanation:

The slope is m=y2-y1/x2-x1=3-2/-8-3=1/-11=-1/11

Equation of a line is

y-y1=m(x-x1)

y-2= - 1/11 (x-3)

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !