Y is inversely proportional to 7I+x.
When x = 8, y = 2.
Find y when x= 15.

I am taking 7I+x to  mean 71+ x.

 y=1.837

Step-by-step explanation:

Step 1

Let y is inversely proportional to 7I+x be  mathematically be written as

y ∝ 1/7I+x

Introducing our proportionality of constant , K we have that

y ∝ 1/7I+x

y =K 1/7I+x

y= K/ 7I+xh

Step 2

so when x= 8, and y =2,  k becomes

y= K/ 7I+x

k=  y x (7I+x)

=2 x (71 + 8)

2x 79

=158

 when x= 15, y =?

y= K/ 7I+x

y= 158/  71 + 15

y=158/86

y=1.837

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.