Given: 2 AgNO3 + Cu -> Cu(NO3)2 + 2 Ag How many grams of AG can be produced if 200.0g of AgNO3 used?

127 g of Ag are made in the reaction.

Explanation:

Reaction is:  2 AgNO₃ + Cu → Cu(NO₃)₂ + 2 Ag

If we only have data from nitrate, we assume the Cu is in excess.

We determine the moles of silver nitrate:

Mass / Molar mass → 200 g / 169.87 g/mol = 1.18 moles

Ratio is 2:2. If 2 moles of silver nitrate produce 2 moles of Ag, then

1.18 moles of salt, will produce 1.18 moles of silver

We convert mass to moles:

1.18 mol . 107.87 g/mol = 127 g

thats how its supposed to be

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