The radius of a right circular cylinder is increasing at the rate of 7 in./s, while the height is decreasing at the rate of 3 in./s. At what rate is the volume of the cylinder changing when the radius is 17 in. And the height is 5 in.?

1014.73 in³/s

Step-by-step explanation:

We know the volume of a cylinder, V = πr²h where r = radius of cylinder and h = height of cylinder.

Now, to find the rate of change of volume, we differentiate it with respect to time. So

dV/dt = d(πr²h)/dt

= πhdr²/dr × dr/dt + πr²dh/dh × dh/dt

= 2πrh × dr/dt + πr² × dh/dt

when r = 17 in, dr/dt = rate of change of radius = + 7 in/s, h = 5 in and dh/dt = rate of change of height = - 3in/s (negative since it is decreasing).

So, dV/dt = 2πrh × dr/dt + πr² × dh/dt

= 2π × 17 in × 5 in × (+ 7 in/s) + π(17 in)² × (- 3 in/s)

= 1190π - 867π

= 323π in³/s

= 1014.73 in³/s

30005

yes ok                                            

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation: