A rectangular field is 10m longer than wide. The area of the field is 2000m². Find the perimeter of the field.

180m

Step-by-step explanation:

Let L = length of field,

W = width of field,

A = field area = 2000 m^2

Lenght = Width + 10m

Let Lenght= x

Width=y

A = X ×Y = (Y + 10)Y= 2000

Y^2 + 10Y- 2000 = 0

Solving using Quadratic eqn with plot

Y= 40 or -50 but we go for the positive root

Width=40m

Length= 40m +10m

= 50m

Perimeter= 2(l+w)

=2(50+40)

180m

Hence, the perimeter is 180 m

CHECK THE ATTACHMENT FOR THE QUADRATIC PLOT

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm

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