What's the sum of an infinite geometric series if the first term is 156 and the common ratio is 2∕3?

468

Step-by-step explanation:

Formula for infinite sum of geometric series is;

S_∞ = a1/(1 - r)

Where;

a1 is first term

r is common ratio

We are given;

a1 = 156

r = ⅔

Thus;

S_∞ = 156/(1 - ⅔)

S_∞ = 156/(⅓)

S_∞ = 468

i could probably can you me with a question of mine?

step-by-step explanation:

30 units^2

step-by-step explanation:

area is l × w

the length is 3

and the width is 10

3 × 10= 30 units squared