Water is flowing down through the pipe shown in the drawing. point a is 0.410 m higher than
b. the speed of the water at a and b are va = 5.00 m/s and vb = 3.24 m/s. determine the difference pb - pa in pressures between b and
a. the density of water is 1.00 × 103 kg/m3.

Bernoulli’s principle can be stated in the form:

(1/2)v^2 + gh + p/rho = constant

where v = velocity

 g= 9.8 m/s^2

h = height = 0.41 m

p = pressure

rho = density  = 1.00 × 103 kg/m3

In this case we can equate points A and B:

(1/2)vA^2 + ghA + pA/rho =(1/2)vB^2 + ghB + pB/rho

Rearranging the equation to get PB-PA and substituting the given values:

pB – pA = ρ (0.5vA^2 - 0.5vB^2 + g(hA-hB))

pB – pA = 1000 (0.5*5^2 – 0.5*3.24^2 + 9.8*0.41)

pB-pA = 11,269.2 Pa = 11.3 kPa

b) returns freshwater to the earth.

c) returns freshwater to the earth.c) occurs after condensation.

d) returns freshwater to the earth.c) occurs after condensation.d) roughly equal to the amount of evaporation.

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friction

explanation:

they us to move forward and backwards