What is the difference between the let statements of consecutive even integers and consecutive odd integers

Answer and Step-by-step explanation:

The word, "Consecutive" means, "Back-to-back" or "One after the other." Therefore, consider these integers:

1, 2, 3, 4, 5, 6, 7, 8, . . .

If we write down these integers in such a way that only even integers follow back-to-back, we have:

2, 4, 6, 8, . . .

If we write down these integers in such a way that only odd integers follow back-to-back, we have:

1, 3, 5, 7, . . .

Since 2, 4, 6, 8, . . . Are all even integers that follow back-to-back, then this is known of consecutive even integers.

Since 1, 3, 5, 7, . . . Are all odd integers that follow back-to-back, then this is known of consecutive odd integers.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.