A plane is flying at a heading of 125° at a speed of 320 mph. The wind is blowing from due North at a speed of 35 mph. Find the ground speed and the course of the plane. (Note: The course must be between 0° and 360°, where due North corresponds to a course of 0°, due East to a course of 90°, due South to a course of 180°, and due West to a course of 270°.)

Step-by-step explanation:

= Velocity of plane = 320 mph

= Velocity of wind = 35 mph

= Angle between wind and plane directions =

From triangle law we have resultant

Direction is given by

The magnitude of the plane is moving at an angle of .

what the question so we can you out

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18