Determine the oxidation number of
Sulphur in Sodium thiosulphate

The oxidation number of  Sulphur = +2

General formula for determining Oxidation Numbers :

1. The number of oxidation of single element atoms = 0. Examples of Ar, Mg, Cu, Fe, N₂, O₂, etc. = 0

Group I : +1

Group II : +2

H in compound = +1, except metal hydride compounds (Hydrogen which binds I or II groups) oxidation number H = -1, for example, LiH, MgH₂, etc.

2. Oxidation number O in compound = -2, except OF2 = + 2 and in peroxide (Na₂O₂, BaO₂) = -1 and superoxide, for example KO₂ = -1/2.

3 The oxidation number in a non-filled compound = 0,

The total amount of oxidation in ion = ion charge, Example NO₃⁻ = -1

Sodium thiosulphate - Na₂S₂O₃

Oxidation number Na = +1 ⇒x2 = +2

Oxidation number O = -2 ⇒x3 = -6

Oxidation number Na₂S₂O₃ = 0

2.Na+2.S+3.O=0

2.+1+2.S+3.(-2)=0

2+2S-6=0

-4+2S=0

2S=4

S=+2

jjj89t'ji; it hink the answer is your mom is not si