diagram 7(i) shows a square with area of 64cm² formed using a string. The string is cut to form another two congruent rectangles with length 5 cm, as shown in diagram 7(ii).Calculate the area , one of the rectangles. If u guys can help me solve this, u guys really save my life. I need to submit tomorrow morning.

The area of one rectangle is 15 cm²

Step-by-step explanation:

The given parameters are;

The area of the square = 64 cm²

The length of the rectangles = 5 cm

The formula for the area of a square = (Side length)² = S²

Therefore, whereby the side length of the given square = S, we have;

Area of the square = 64 = S × S = S²

S = √(64 cm²) = 8 cm

The side length of the square = 8 cm

The perimeter of a square = The length of the string = Side length × 4 = 8 cm × 4 = 32 cm

∴ The perimeter of a square = The length of the string = 32 cm

The length of the string = The perimeter of the two congruent rectangle = 32 cm

Therefore;

The perimeter of each rectangle = 32/2 cm = 16 cm

Given that the length, L of the side of each rectangle is L = 5 cm, we have;

The perimeter of a rectangle = 2 × L + 2 × W

Where;

W = The width

The perimeter of the rectangle = 16 = 2 × 5 + 2 × W

2 × W = 16 - 2 × 5 = 6

W = 6/2 = 3

W = 3 cm

The width, W, of each rectangle is W = 3 cm

The area of one rectangle = W × L = 3 cm × 5 cm = 15 cm²

The area of one rectangle = 15 cm².

ok

step-by-step explanation:

correct

step-by-step explanation: