The perimeter of a rectangle is 56 inches it's with is 6 inches less than its length find the lenth and the width

P = 2(L + W)
P = 56
W = L - 6

56 = 2(L + L - 6)
56 = 2(2L - 6)
56 = 4L - 12
56 + 12 = 4L
68 = 4L
68/4 = L
17 = L <length (L) = 17 inches

W = L - 6
W = 17 - 6
W = 11 <== width (W) = 11 inches

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!