David thought that he would have to buy 12 packages of hot dog buns and 10 packages of hot dogs to have one bun for each hot dog. What is the LEAST amount of each David would need to buy to have an equal number of hot dogs and buns?

Given that,

No of package of hot dog buns = 12

No of package of hot dog = 10

To find,

The least amount of each David would need to buy.

Solution,

To find least amount of each, we must find the LCM of both numbers i.e. 12 and 10.

Prime factorisation of 12 = 2 × 2 × 3

Prime factorisation of 10 = 2 × 5

LCM of (12,10) = 2 × 2 × 3 × 5

= 60

He should buy,

60/12 = 5 package of hot dog buns and 60/10 = 6 package of hot dog.

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w

im guessing (23,14). hope this : )