Which of the following reactions will have the largest equilibrium constant (k) at 298 k? which of the following reactions will have the largest equilibrium constant (k) at 298 k? 2 hg(g) + o2(g) → 2 hgo(s) δg° = -180.8 kj caco3(s) → cao(s) + co2(g) δg° =+131.1 kj 3 o2(g) → 2 o3(g) δg° = +326 kj fe2o3(s) + 3 co(g) → 2 fe(s) + 3 co2(g) δg° = -28.0 kj it is not possible to determine without more information.

2 Hg(g) + O₂(g) → 2 HgO(s) ΔG° = -180.8 kJ

Explanation:

If we know the ΔG° of a chemical reaction it is possible to calculate the equilibrium constant (k) of this procedure with the next equation:

ln Keq = -ΔG° / RT (1)

Where: Keq is equilibrium contant, ΔG° is standard state free energy change, R is gas constant and T is temperature.

Watching (1), it is possible to know that the large negative ΔG° the largest equilibrium constant. That is because R and T are always positive and to cancel the negative of equation it is necessary that ΔG° be negative.

Knowing this, is the oxidation of Hg the reaction that has the largely negative ΔG°. So, this reaction will have the largest equilibrium constant.

2 Hg(g) + O₂(g) → 2 HgO(s) ΔG° = -180.8 kJ

CaCO₃(s) → CaO(s) + CO₂(g) ΔG° =+131.1 kJ

3 O₂(g) → 2 O₃(g) ΔG° = +326 kJ

Fe₂O₃(s) + 3 CO(g) → 2 Fe(s) + 3 CO₂(g) ΔG° = -28.0 kJ

I hope it helps!

the electrical  conductivity  of asolution  of an electrolyte is measured by determining the resistance of thesolution  between two flat or cylindrical electrodes separated by a fixed distance.

20 drops hope this