Mathematics, 10.12.2020 01:20 marissalwilliams3

PLEASE HELP! The dimensions of a rectangle are 2 cm by 3 cm. The length and width are increasing at a rate of 3 cm/sec. Write a function for the area of the rectangle in terms of time.

A. A=9t^2 +6
B. A=(2t)(3t)
C. A=(2)(3)(3t)
D. A=(2+3t)(3+3t)

Answers: 1

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PLEASE HELP! The dimensions of a rectangle are 2 cm by 3 cm. The length and width are increasing at a rate of 3 cm/sec. Write a function for the area of the rectangle in terms of time. A. A=9t^2 +6 B. A=(2t)(3t) C. A=(2)(3)(3t) D. A=(2+3t)(3+3t)

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Another question on Mathematics

PLEASE HELP! The dimensions of a rectangle are 2 cm by 3 cm. The length and width are increasing at a rate of 3 cm/sec. Write a function for the area of the rectangle in terms of time.

A. A=9t^2 +6
B. A=(2t)(3t)
C. A=(2)(3)(3t)
D. A=(2+3t)(3+3t)