The 6: oo a. m temperatures for four consecutive days in the town of lincoln were -21.1c , -7.8c , -14.3c and -7.2c what was the average 6: oo am temperature for the four days

From the information given, the temperature given is -21, -7.8, -14.3 and -7.2

We see that none of these  temperature readings are above 0 degrees Celsius, all are below therefore we can go ahead and treat them uniformly.

We will add them together without their minus sign and calculate the average, so:

21.1 + 7.8 + 14.3 + 7.2 = 50.4

We divide the answer by 4, so:

50.4  ÷ 4 = 12.6

We now revert back to our minus sign so the average 6.00 am temp is  -12.6 °c

i think is g(1)=-1.

hope that i can

fd

step-by-step explanation: